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6x^2=550
We move all terms to the left:
6x^2-(550)=0
a = 6; b = 0; c = -550;
Δ = b2-4ac
Δ = 02-4·6·(-550)
Δ = 13200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13200}=\sqrt{400*33}=\sqrt{400}*\sqrt{33}=20\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{33}}{2*6}=\frac{0-20\sqrt{33}}{12} =-\frac{20\sqrt{33}}{12} =-\frac{5\sqrt{33}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{33}}{2*6}=\frac{0+20\sqrt{33}}{12} =\frac{20\sqrt{33}}{12} =\frac{5\sqrt{33}}{3} $
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